(5x-4)(5x+4)=25x^2-16

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Solution for (5x-4)(5x+4)=25x^2-16 equation:


Simplifying
(5x + -4)(5x + 4) = 25x2 + -16

Reorder the terms:
(-4 + 5x)(5x + 4) = 25x2 + -16

Reorder the terms:
(-4 + 5x)(4 + 5x) = 25x2 + -16

Multiply (-4 + 5x) * (4 + 5x)
(-4(4 + 5x) + 5x * (4 + 5x)) = 25x2 + -16
((4 * -4 + 5x * -4) + 5x * (4 + 5x)) = 25x2 + -16
((-16 + -20x) + 5x * (4 + 5x)) = 25x2 + -16
(-16 + -20x + (4 * 5x + 5x * 5x)) = 25x2 + -16
(-16 + -20x + (20x + 25x2)) = 25x2 + -16

Combine like terms: -20x + 20x = 0
(-16 + 0 + 25x2) = 25x2 + -16
(-16 + 25x2) = 25x2 + -16

Reorder the terms:
-16 + 25x2 = -16 + 25x2

Add '16' to each side of the equation.
-16 + 16 + 25x2 = -16 + 16 + 25x2

Combine like terms: -16 + 16 = 0
0 + 25x2 = -16 + 16 + 25x2
25x2 = -16 + 16 + 25x2

Combine like terms: -16 + 16 = 0
25x2 = 0 + 25x2
25x2 = 25x2

Add '-25x2' to each side of the equation.
25x2 + -25x2 = 25x2 + -25x2

Combine like terms: 25x2 + -25x2 = 0
0 = 25x2 + -25x2

Combine like terms: 25x2 + -25x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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